Sequence and Series – Arithmetic and Geometric Progressions Chapter 6 Exercise 6B CA foundation maths solutions

CA foundation maths solutions for Chapter 6 Exercise 6B Sequence and Series – Arithmetic and Geometric Progressions are given.

First you should study the CA maths textbook lesson chapter 6 very well.

You must observe and practice all example Problems and solutions which are given in the textbook.

You can observe the solutions given below. You will be try them in your own way.

CA foundation maths solutions 

Sequence and Series – Arithmetic and Geometric Progressions

Exercise 6A

Exercise 6B

Exercise 6C

CA maths Sequence and Series – Arithmetic and Geometric Progressions solutions Exercise 6B chapter 6

CA foundation maths solutions

Chapter 6

Sequence and Series – Arithmetic and Geometric Progressions

Exercise 6B

5. The last term of the series 1, 2, 4, …,. to 10 terms is

6. The last term of the series 1, – 3, 9, – 27 up to 7 terms is

8. The sum of the series – 2, 6, – 18, ….. to 7 terms is.

9. The sum of the series 243, 81, 27, …… to 8 terms is

11. The second term of a G P is 24 and fifth term is 81. The series is

12. They sum of 3 numbers of a G P is 39 and their product is 729. The numbers are

Chapter 6 Exercise 6B solutions CA maths solutions

13. In a G. P the product of the first three terms 27/8. The middle term is

14. If you save 1 paise today, 2 paise the next day 4 paise the succeeding day and so on, then your total savings in two weeks will be

15. Sum of n terms of the series for plus 4 + 44 + 444 + …. is

16. Sum of n terms of the series 0.1 + 0.11 + 0.111 + ……  is

17. The sum of the first 20 terms of a G.P is 244 times the sum of its first 10 terms. The common ratio is

18. Sum of the series 1 + 3 + 9 + 27 + is 364. The number of terms is

19. The product of three numbers in GP is 729 and the sum of space is 819. The numbers are

20. The sum of the series 1 + 2 + 4 + 8 + ……. to n term

21. The sum of the infinite G.P 14, – 2, + 2/7, – 2/ 49 + …… is.

22. The sum of the infinite G.P. 1 – 1/ 3 + 1/9 – 1/27 + ….. is.

23. The number of terms to be taken so that 1 + 2 + 4 + 8 + will be 8191 is

24. Four geometric means between 4 and 972 are

Note : You can observe the solutions and try them in your own method.

Inter Maths solutions

SSC maths solutions

NIOS maths solutions 

General maths solutions 

Leave a Comment

Your email address will not be published. Required fields are marked *