Class 6 maths Exercise 3.4 solutions

NCERT mathematics class 6 chapter 3 Playing with Numbers exercise 3.4 solutions are given. You should study the textbook lesson Playing with Numbers very well. You should also observe and practice all example problems and solutions given in the textbook. You can observe the solutions given below and try them in your own method. NCERT maths class 6 solutions Exercise 3.1 Exercise 3.2 Exercise 3.3 Exercise 3.4 Exercise 3.5 Exercise 3.6 Exercise 3.7 CA foundation maths solutions 

Chapter 3 exercise 3.4 solutions Playing with Numbers NCERT class 6 maths

CBSE class 6 maths solutions Chapter 3 Playing with Numbers Exercise 3.4

class 6 maths exercise 3.4 Playing with Numbers Chapter 3 NCERT

Problem 1 1. Find the common factors of: a. 20 and 28,       b. 15 and 25 c. 35 and 50,       d. 56 and 120 Solutions: a. 20 and 28 The factors of 20 = 1, 2, 4, 5, 10, 20 The factors of 28 = 1, 2, 4, 7, 14, 28 The common factors of 20 and 28 =1, 2, 4 b. 15 and 25 The factors of 15 = 1, 3, 5, 15 The factors of 25 = 1, 5, 25 The common factors of 15and 25 = 1, 5 c. 35 and 50 The factors of 35 = 1, 5, 7, 35 The factors of 50= 1, 2, 5, 10, 25, 50 The common factors of 35 and 50 = 1, 5 d. 56 and 120 The factors of 56 = 1, 2, 4, 7, 5, 8, 28, 56 The factors of 120 = 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 60, 120 The common factors of 56 and 120 = 1, 2, 4, 8 Problem 2 2. Find the common factors of: a. 4, 8 and 12,          b. 5, 15 and 25 Solutions: a. 4, 8 and 12 The factors of 4 = 1, 2, 4 The factors of 8 = 1, 2, 4, 8 The factors of 12 = 1, 2, 4, 6, 12 The common factors of 4, 8 and 12 = 1, 2, 4 b. 5, 15 and 25 The factors of 5 = 1, 5 The factors of 15 = 1, 3, 5, 15 The factors of 25 = 1, 5, 25 The common factors of 5, 15 and 25 = 1, 5 Problem 3 3. Find first three common multiples of: a. 6 and 8,        b. 12 and 18 Solutions: a. 6 and 8 The multiples of 6 = 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96, ……. The multiples of 8 = 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, …… The first three common multiples of 6 and 8 = 24, 48, 72 b. 12 and 18 The multiples of 12 = 12, 24, 36, 48, 60, 72, 84, 96, 108, 120, …… The multiples of 18 = 18, 36, 54, 72, 90, 108, …. The first three common multiples of 12 and 18 = 36, 72, 108 Problem 4 4. Write all the numbers less than 100 which are common multiples of 3 and 4. Solutions: The multiples of 3 = 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99. The multiples of 4 = 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96. The common multiples of 3 and 4 = 12, 24, 36, 48, 60, 72, 84, 96. Problem 5 5. Which of following numbers are co – prime? a. 18 and 35,          b. 15 and 37 c. 17 and 68,          d. 30 and 415 e. 216 and 215,      f. 81 and 16 Solutions: a. 18 and 35 The factors of 18 = 1, 2, 3, 6, 9, 18 The factors of 35 = 1, 5, 7, 35 The common factors of 18 and 35 = 1 Therefore, both have only one common factor 1 as they are co – prime numbers. b. 15 and 37 The factors of 15 = 1, 3, 5, 15 The factors of 37 = 1, 37 The common factors of 15 and 37 = 1 Therefore, both have only one common factor 1 as they are co – prime numbers. c. 30 and 415 The factors of 30 = 1, 2, 3, 5, 6, 15, 30 The factors of 415 = 1, 5, 83, 415 The common factors of 30 and 415 = 1, 5 Therefore, both have more than one common factor, as they are not co – prime numbers. d. 17 and 68 The factors of 17 = 1, 17 The factors of 68 = 1, 2, 4, 17, 34, 68 The common factors of 17 and 68 = 1, 17 Therefore, both have more than one common factor as they are not co-prime numbers. e. 216 and 215 The factors of 216 = 1, 2, 3, 4, 6, 8, 12, 24, 27, 36, 54, 72, 108, 216 The factors of 215 = 1, 5, 43, 215 The common factors of 216 and 215 = 1 Therefore, both have only one common factor 1 as they are co – prime numbers. f. 81 and 16 The factors of 81 = 1, 3, 9, 27, 81 The factors of 16 = 1, 2, 4, 8, 16 The common factors of 81 and 16 = 1 Therefore, both have only one common factor 1 as they are co – prime numbers. Problem 6 6. A number is divisible by both 5 and 12. By which other number will that number be always divisible? Solution: The first common multiple of both 5 and 12 = 60 5 × 12 = 60 The number must be divisible by 60. 7. A number is divisible by 12. By what other number will that number be divisible? Solution: 12 is divisible by 12. The factors of 12 = 1, 2, 3, 4, 6, 12 Therefore, the number also be divisible by 1, 2, 3, 4, 6. Note: Observe the solutions and try them in your own method. Inter maths 1A solutions SSC maths class 10 solutions NCERT maths class 7 solutions NIOS maths 311 book 2 solutions for some chapters