Sequence and Series – Arithmetic and Geometric Progressions Chapter 6 Exercise 6C CA foundation maths solutions

CA foundation maths solutions for Chapter 6 Exercise 6C Sequence and Series – Arithmetic and Geometric Progressions are given.

First you should study the CA maths textbook lesson chapter 6 very well.

You must observe and practice all example Problems and solutions which are given in the textbook.

You can observe the solutions given below. You will be try them in your own way.

CA foundation maths solutions 

Sequence and Series – Arithmetic and Geometric Progressions

Exercise 6A

Exercise 6B

Exercise 6C

CA maths Sequence and Series – Arithmetic and Geometric Progressions solutions Exercise 6C chapter 6

CA foundation maths solutions

Chapter 6

Sequence and Series – Arithmetic and Geometric Progressions

Exercise 6C

1. Three number are in AP and theie is sum is 21. If 1, 5, 15 are added to them respectively,  they form a G.P.  The numbers are

3. The sum of the Infinite series 1 + 2/3 + 4/9 + ….. is

4. The sum of the first two terms of a G.P. is 5/3 and the sum to infinity of the series is 3. The common ratio is

6. The sum of three numbers in GP is 70. If the two extremes by multiplied each by 4 and the mean by 5, the products are in AP. The numbers are

7. The sum of 3 numbers in AP is 15. If 1, 4 and 19 be added to them respectively, the results are is G.P. The numbers are

9. If the terms 2x , (x + 10) and (3x + 2) be in A.P., the value of x is

10. If A be the A. M. of two positive unequal quantities x and y and G be their G.M, then

11. The A. M. of two positive numbers is 40 and their G.M. is 24. The numbers are

12. Three numbers are in A.P. and their sum is 15. If 8, 6, 4 be added to them respectively, the numbers are in G.P. The numbers are

13. The sum of four numbers in G.P. is 60 and the A.M. of the first and the last is 18. The numbers are

14. A sum of Rs. 6240 is paid off in 30 installments such that each installment is Rs. 10 more than proceeding installment. The value of the first installment is

Chapter 6 Exercise 6C solutions CA maths solutions

16. If x, y, z are in A.P. and x, y, (z + 1) are in G.P. then

17. The numbers x, 8, y are in G.P. and the numbers x, y,  – 8 are in A.P. The value of x and y are

19. The sum of n terms of a G.P. whose first term 1 and the common ratio 1/2, is equal to 1 127/128. The value of n is

21. If x,  y, z are in G.P., then

22. The sum of all odd numbers between 200 and 300 is

23. The sum of all natural numbers between 500 and 1000 which are divisible by 13, is

24. If unity is added to the sum of any number of terms of the A.P. 3, 5, 7, 9, ….. the resulting sum is

25. The sum of all natural numbers from 100 to 3000 which are exactly divisible by 4 or 5 is

26. The sum of all natural numbers from 100 to 3000 which are exactly divisible by 4 or 5 is

27. A person pays Rs. 975 by monthly installment each less than the former by Rs. 5. The first installment is Rs. 100. The time by which the entire amount will be paid is

The entire amount will be paid in 15 months.

28. A person saved Rs. 16,500 in 10 years. In each year after the first year he saved Rs. 100 more than he did in the proceeding year. The amount of money is saved in the first year was

29. At 10% C.I. p.a., a sum of money accumulate to Rs 9625 in 5 years. The sum invested initially is

30. The population of a country was 55 crores in 2005 and is growing at 2% p.a. C.I. The population is the year 2015 is estimated as

Note : You can observe the solutions and try them in your own method.

Inter Maths solutions

SSC maths solutions

NIOS maths solutions 

General maths solutions 

Leave a Comment

Your email address will not be published. Required fields are marked *