Basic Concepts of Permutations and Combinations solutions Exercise 5D CA maths chapter 5
CA foundation maths solutions Chapter 5 Basic Concepts of Permutations and Combinations Exercise 5D are given.
You should study the textbook lesson Basic Concepts of Permutations and Combinations very well.
You must practice all example Problems and solutions which are given in the textbook.
You can observe the solutions which are given below and try them in your own way.
Basic Concepts of Permutations and Combinations
CA maths solutions Exercise 5D chapter 5 Basic Concepts of Permutations and Combinations
CA foundation maths solutions
Chaper 5
Basic Concepts of Permutations and Combinations
Exercise 5D
1. The letters of the word ‘CALCUTTA’ and ‘AMERICA’ are arranged in all possible ways. The ratio of the number of their arrangements is
2. The ways of selecting 4 letters from the word ‘EXAMINATION’ is
3. The number of different words that can be formed with 12 consonants and 5 vowels by taking for consonants and 3 vowels in each word is
4. Eight guests have to be seated 4 on each side of a long rectangular table to particular guests desire to sit on one side of the table and 3 on the other side. The number of ways in which the sitting arrangements can be made is
5. A question paper contains 6 questions, each having an alternative. The number of ways an examine can answer one more questions is
7. The number of words that can be made by rearranging the letters of the word ‘APURNA’ so that vowels and consonants appear alternate is
8. The number of arrangement of the letters of the word ‘COMMERCE’is.
Solution:
The word has 8 letters. The letters E, C M are repeated twice
The number of arrangements can be done in
8!/2! 2! 2! 7! .
9. A candidate is required to answer 6 out of 12 questions which are divided into two groups containing 6 questions in each group. He is not permitted to attempt not more than four from any group. The number of choices are
10. The results of 8 matches (Win, Loss or Draw) are to be predicted. The number of different forecasts containing exactly 6 correct result is
11. The number of ways in which 8 different beads be strong and a necklace is
Solution:
Let one of bead has to give position.
Remaing 7 are arranged in a circular way in clockwise or anticlockwise direction.
The number of ways = 7!/2 = 5040/2 = 2520
Basic Concepts of Permutations and Combinations CA foundation maths solution Exercise 5D
12. The number of different factors the number of 75,600 has is
13. The number of 4 digit numbers formed with the digital digits 1, 1, 2, 2, 3, 4 is.
14. The number of ways a person can contribute to a fund out of 1 ten-rupee note, 1 five-rupee note, 1 two-rupee note and 1 one rupee note is
15. The number of ways in which 9 things can be divided into twice groups containing 2, 3 and 4 things respectively is
17. (2n)! can be written as.
18. The number of even numbers greater than 300 can be formed with the digits 1, 2, 3, 4, 5 without repetition is
19. 5 letters are written and there are five letter-boxes. The number of ways the letters can be dropped into the boxes, are in each
Note: You can observe the solutions. You will try them in your own method.